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1. A lead developer reviewing code from one of the programmers found the following code. What should the
programmer be told about BY NAME assignments?
DCLl STR1, 3FB15 FIXED BIN (15), 3 CH10 CHAR (10), 3 NAME CHAR (25). 3 ADDR CHAR (30), 3
FB31 FIXED BIN(31);
DCL 1 STR2, 3 FB31 FIXED BIN (31), 3 FB31B FIXED BIN (31), 3 NAME CHAR (20), 3 ADDR CHAR
(30), 3 CH20 CHAR (20);
STR2 = STR1, BY NAME;
A) There is nothing wrong with using BY NAME assignments in this situation.
B) They can have inadvertent side effects and the code should be analwed.
C) They do not work in this case and the code should be replaced by individual assignments.
D) They are incorrect and should be replaced by individual assignments.
2. Given the following code, which is the only valid way to convert Q to P?
DCL Q OFFSET;
DCL P POINTER;
DCLX CHAR(100)BASED;
DCL A AREA(6000);
ALLOC X SET(Q) IN(A);
A) P = POINTERVALUE(Q);
B) P = ADDR(A) + Q;
C) P = POINTER(Q,A);
D) P = Q;
3. Given the following pseudocode inside a loop, where should the COMMIT action be placed assuming that
there is always a one-to-many relationship between header and detail tables?
1 Find header row 2 IF found 3 Update header row 4 Find detail row 5 IF found THEN 6 Update detail
rows 7 ELSE 8 ENDIF 9 ENDIF
A) After line 6
B) After lines 3, 8, and 9
C) After line 3
D) After line 8
4. In the following example what value will be printed to SYSPRINT, if any, from the PUT LIST in PGM_A?
PGM_A PROC;
DCL INPARM CHAR (10) INIT('FIRST CALL);
DCL P_OUT PTR;
DCL OUTPARM CHAR(10) BASED (P_OUT);
DCL PGM_B ENTRY(CHAR(10),PTR) EXTERNAL:
CALL P0MB (INPARM,P OUT);
IF OUTPARM = 'RESULT 'THEN
DO;
INPARM = ";
CALL PGM_B (INPARM,P_OUT);
END;
PUT LIST(OUTPARM);
END;
PGM_B: PROC(INPARMP_OUT);
DCL INPARM CHAR (10);
DCL P_OUT PTR;
DCL OUTPARM CHAR (10) INIT(");
P_OUT = ADDR(OUTPARM);
IF INPARM ='FIRST CALL THEN
OUTPARM = 'RESULT ';
ELSE
OUTPARM = 'NO RESULT';
END;
A) Blanks
B) Unpredictable
C) 'NO RESULT'
D) 'RESULT'
5. Given the following declarations, which is the WORST way of setting D from 5?
DCL 1 S,
2 A(100) CHAR(1),
2 B(100) CHAR(2),
2 C(100) CHAR(3);
S = "; DCL D CHAR(600);
DCLI BIN FIXED(31);
A) D = STRING(S);
B) D = STRING(A) !! STRING(S) !! STRING(C);
C) CALL PLIOVER(ADDR(D)ADDR(S),600);
D) DO I = 1 TO 100;
SUBSTR(D,I,1) = S.A(l);
SUBSTR(D,1 01 + ((I-1) *2),2) = S.B(I);
SUBSTR(D,301 + ((I-1) *3),3) = S.C(I);
END;
Solutions:
| Question # 1 Answer: B | Question # 2 Answer: C | Question # 3 Answer: D | Question # 4 Answer: B | Question # 5 Answer: D |
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